(-4/25)(x+5)^-6/5=0

Solution for (-4/25)(x+5)^-6/5=0 equation:

(-4/25)(x+5)^-6/5=0


Domain of the equation: 25)(x+5)^!=0

x∈R


We multiply parentheses ..

(-4x^2-4/25*5)^-6/5=0

We calculate fractions


((-4x^2-4*5)/()+()/()=0


We calculate terms in parentheses: +((-4x^2-4*5)/()+()/(), so:

(-4x^2-4*5)/()+()/(

We add all the numbers together, and all the variables

(-4x^2-4*5)/()+1

We multiply all the terms by the denominator


(-4x^2-4*5)+1*()

We add all the numbers together, and all the variables

(-4x^2-4*5)

We get rid of parentheses

-4x^2-4*5

We add all the numbers together, and all the variables

-4x^2-20

Back to the equation:

+(-4x^2-20)


We get rid of parentheses

-4x^2-20=0

a = -4; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·(-4)·(-20)
Δ = -320
Delta is less than zero, so there is no solution for the equation